Works because (√y)' = 1/2√y = 1/2x. It's Newton's method of iteratively chasing tangent lines
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Or it could just be Newton's binomial theorem, if you use just the first two terms of the expansion
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That's a first order NR. If you use second order you get this formula which converges extremely fast ( using sqrt 17 and 4 as initial guess, the first iteration returns 4 digits correct, second iteration 14 digits ok)pic.twitter.com/uc0vRuPoyd
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isn't this just a fancy newton rapson?
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This is essentially the method used by the Babylonians. It's around 5000 years old. It was used for calculations like this:pic.twitter.com/C1749o3snd
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Woah, trippy lighting illusion, all the writing looks like bumps instead of indents
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2 + 2 = 4 - 1 = 3 quick mafffs!
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This is not quite right. x^2 has to be less than y, otherwise you subtract the value d/2x.
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Well in that case d<0 making the term d/2x negative and automatically changing the plus sign to minus.
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Here we go, my Java implementation of this algorithm. pastebin: https://pastebin.com/SNh1y1gK I'm sure this can be improved, but I literally just threw this together in a couple minutes and now wanna play
#Flotsam ^^pic.twitter.com/YP5aVSE2Q6
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If: highdiff = high - targetnumber It isn't get negative values? first iteration: highdiff = 1 - 17 = -16
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