Here's a funny alternative: throw the die, when it stops look at your watch and pick the last digit of the seconds [0,9], now add 1 and you have a uniform distribution [1,10]
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Thanks. Twitter will use this to make your timeline better. UndoUndo
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If you want a whole number: throw it until you don't get a 6. Then throw it again and add the 1 to 5 number from Step 1, to 0 or 5, depending on whether this throw is even or odd.
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I think is better with prime numbers and 0.
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How about roll the die until you get five or less. Then roll again. If you get 3 or less keep the first number. Otherwise add 5. Uniform 1 to 10.
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Instructions unclear, can't see how to get 9 or 10 with this.
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1. Throw 2 dices 2. If sum equals 7, restart. 3. There are 30 possible ending results, so just associate 3 results each for 1,2,3,...,10. eg. (1,1); (1,2); (2,1) could be for 1.
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Better yet, pick 10 ordered pairs of two numbers between 1 and 6 and associate them to numbers 1 through 10 and roll a dice twice until one of these pairs shows up. E.g., roll a dice until it is 1 thru 5, roll again until it is 1 or 2, and number = first roll + 5*second roll - 5.
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This Tweet is unavailable.
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Looks like something from an independent research institute based in Singapore
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Now the question: How big N must be in order to consider the distribution uniform??
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At least N = 30
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1 - Throw the die 𝑁 times and sum the results (S)
2 - Calculate the residue class (mod 10)
3 - The distribution on [1,10] tends to a uniform distribution as 𝑁→∞