6! = 10x9x8
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10*9*8 = 10!/7! Therefore... 6! = 10!/7! 6! 7!=10! Which is exactly what was posted.
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6! = 5!3!
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But this is exactly (n!)! = n!(n! - 1)! for n=3.
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How? 6! = 10*9*8
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That's not n! = a!b!
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No it's the only solution know at the moment...
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2! = 2! 1!
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that falls in to the general pattern stated above, where n=3
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