When you use π to calculate πpic.twitter.com/VizGFG0T4M
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When you use π to calculate πpic.twitter.com/VizGFG0T4M
nice one endless loop
That's just the Taylor series expansion of x^x around 0 (write x^x as e^(x*lnx) and then in the Taylor series of e^x substitute x*lnx). There's nothing particularly special about pi in this case
Still cool though
True for any real, positive value of π.
And for any complex with positive real part! For the others you need to know higher complex monodromy. You should read more Euler and less Grothendieck 
Yeah, it's a cheap trick.
Hey Wise Pierre #Fermat: Why we don't just simply say --
(π)^π = π (ln π)
That is: (π raised to the power π) = [ π Multiplied by (Ln π) ] .
Where (Ln π) = Natural Logarithm of π
Think you are missing an “e^” in front of the RHS
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