P(even heads) = P(0 heads) + P(2) + P(4) + P(6) + P(8). Since P(k heads) = P(9-k heads), we see that P(0) = P(9), P(1) = P(8), and so on. So P(even) = P(odd). Since P(even) + P(odd) = 1, then we necessarily have that P(even heads) = 1/2.
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I love how mathematicians need to make long and complicated calculus just to justify what common sense already tells you
PS: I love scientific method, just teasing you a little bit 
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%29.55718 cuz binumeral consistencies overlaps the exponential hyperbolic avocado. You’re welcome.
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Is it too obvious that I suck at math?
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2, 4, 6, 8, who do we appreciate?
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Also, we can state one side must be even and the other one must be odd. Both sides have therefore equal chances of having an even number or apparition.
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There is no reason the answer would be different for odd. So it must be 50%.
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Lots have said 50%. This is best answer to WHY 50% must be correct.
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