True, you need a pen too.
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Is this a conjecture or is there actually a proof for this?
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Wantzel proved it in the XIX century. Basically the problem is equivalent to finding the root of a cubic polynomial. For some cases, that's an irrational number, and constructible irrationals are roots of 2nd degree polynomials. There are cases where trisection is possible (90º).
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It's crazy to think that the method for bisecting an angle with a ruler and compass was already on Euclid's Elements and then it took almost 2000 years for Pierre Wantzel to prove that the trisection was impossible (1837)!pic.twitter.com/YBJ8MrHGho
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Yes like Pitagora's theorem and the Fermat's last theorem....
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WAIT! This was legitimately an extra credit problem in high school, and I could never figure it out. Was the answer simply, cannot be done????
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Cannot be done dude :p
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Only 90° and 180° can be trisected using only compass and straightedge. In "What is Mathematics?" [Oxford University Press, 1996] R. Courant and H. Robbins showed that arbitrary angle can be trisected using a marked ruler.
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Compass and ruler.
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