There are four factorions (in base 10): 1 = 1! 2 = 2! 145 = 1! + 4! + 5! 40585 = 4! + 0! + 5! + 8! + 5! A014080 in the OEIS.
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1 is a factorion in any integer base. 2 is a factorion in all integer bases except binary. In base 10, there are only four factorions: 1, 2, 145 and 40585
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> In base 10, there are only four factorions We've only found four? Or they can only be four? Has it be proven?
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See more with plus-minus at: http://bit.ly/2vPa3im - upto six digits - seven digits under preparationpic.twitter.com/v45JI3OMzb
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Are there any triple factoration bigger than 1!!!,2!!!,3!!!,4!!!?
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Whoa!, I mean W!+h!+o!+a!
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Largest. Needs to fit 10(d-1) > n > 9!d. Doesn’t work for 8 or more, so max has 7 digits. First upper bound therefore 9,999,999. Max sum of 7 factorials is 7!*9 so second upper bound is therefore 2,540,160.
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As such, first factorial is max 2!. Therefore, third upper bound is 2! + 6 * 9! = 2,177,282. So if n is a 7 digit number, the second digit must be 0 or 1. Next upper bound would therefore be 2! + 1! + 5 * 9! = 1,814,403. This contradicts second digit being 0 or 1.
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@zuluagajorge una ñoñada linda, cómo todas.Thanks. Twitter will use this to make your timeline better. UndoUndo
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