I've discovered that a^n * b^n = c^n exists for any n>2 , but unfortunately the proof cannot fit into this tweet. - 21st century Fermat
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@existentialcoms: I've discovered that a^n * b^n = c^n exists for any n>2" actually he 'proved' it couldn't exist. -
@goldsmithee@existentialcoms you're confusing '*' with '+'. For multiplication, school algebra suffices.
End of conversation
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@existentialcoms If anyone actually read twitlonger posts, this wouldn't count as a valid excuse.Thanks. Twitter will use this to make your timeline better. UndoUndo
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@existentialcoms proof for multiplication somewhat trivialThanks. Twitter will use this to make your timeline better. UndoUndo
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@existentialcoms ..thought it was + , not timesThanks. Twitter will use this to make your timeline better. UndoUndo
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@existentialcoms ...and another thing , that you overlooked ... *twitterEyes roll back collectivelyThanks. Twitter will use this to make your timeline better. UndoUndo
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