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eigenrobot's profile
eigenrobot
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@eigenrobot

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eigenrobot

@eigenrobot

robot. friend.

eigenrobot.substack.com
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    eigenrobot‏ @eigenrobot 2 Mar 2019

    eigenrobot Retweeted Good Tweetman

    mildly curious is there a non-degenerate set of a axioms that will produce this resulthttps://twitter.com/Goodtweet_man/status/1102008150096560128 …

    eigenrobot added,

    Good Tweetman @Goodtweet_man
    It’s like asking me to make 1 + 1 = 3, it’s nonsensical
    Show this thread
    5:16 PM - 2 Mar 2019
    • 6 Likes
    • Font of Argh (the coolest) Rhea Myers If you can't abort me, flush me in the toilet Sila Matt Parsons 🏳️‍🌈
    7 replies 0 retweets 6 likes
      1. New conversation
      2. eumemic  🟥‏ @dysmemic 2 Mar 2019
        Replying to @eigenrobot

        Assuming by degenerate you mean inconsistent, doesn’t proving 1 + 1 = 3 imply your axioms are inconsistent? Unless in your theory you can’t manage to prove that 1 + 1 is anything else...

        1 reply 0 retweets 1 like
      3. eumemic  🟥‏ @dysmemic 2 Mar 2019
        Replying to @dysmemic @eigenrobot

        In my number theory the number normally referred to as “2” is instead represented by the symbol “3” and vice versa... in all other respects it’s the same

        0 replies 0 retweets 2 likes
      4. End of conversation
      1.  🦌‏ @kilovh 2 Mar 2019
        Replying to @eigenrobot

        "the whole is greater than the sum of its parts"

        0 replies 0 retweets 1 like
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      1. Morgan‏ @rhoark 2 Mar 2019
        Replying to @eigenrobot

        It would be true in any quotient algebra where 2 is congruent to 3, I guess.

        0 replies 0 retweets 2 likes
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      1. New conversation
      2. chc4‏ @chc40 2 Mar 2019
        Replying to @eigenrobot

        addition of gray codes. 0x1+0x1=0x11. addition only has to be associative and commutative - under different fields you'll get wildly different answers, just like how 255+1=0 under GP(2^8)

        1 reply 0 retweets 5 likes
      3. dji  ☠️ nnius  🇮🇲‏ @djinnius 2 Mar 2019
        Replying to @chc40 @eigenrobot

        This is a great answer but/and gray codes are a different way of writing the natural numbers so of course 0x11 == 2 I like it though, it reminds me of ‘equations’ where you ‘cancel’ numbers from a division and accidentally get the right answer. Strange loops are fun!

        1 reply 0 retweets 1 like
      4. Show replies
      1. New conversation
      2. The Gentleman Sausage‏ @Gent_Sausage 2 Mar 2019
        Replying to @eigenrobot

        I mean if it was less than two it could be trivially done with vector math. Not sure how to get more than two from 1 + 1 without some really absurd hax, like asserting unspecified units were present all along. "One pair and one single is three," that sort of thing.

        1 reply 0 retweets 1 like
      3. The Gentleman Sausage‏ @Gent_Sausage 2 Mar 2019
        Replying to @Gent_Sausage @eigenrobot

        Or "the symbols are arbitrary so we can imagine a system of writing numbers in which 3 is this many [ | | ] and 2 is this many [ | | | | ] and 4 is this many [ | | | ]" Or "1 + 1 = 3 because I said so and I'll keep beating you until you agree"

        1 reply 0 retweets 1 like
      4. Show replies
      1. New conversation
      2. Font of Argh (the coolest)‏ @MeFromBefore 2 Mar 2019
        Replying to @eigenrobot

        what do you have against degenerate axioms

        1 reply 0 retweets 1 like
      3. dji  ☠️ nnius  🇮🇲‏ @djinnius 2 Mar 2019
        Replying to @MeFromBefore @eigenrobot

        trivial is boring

        0 replies 0 retweets 2 likes
      4. End of conversation

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