@anrizal f :: [a] -> [a]; f [] = []; Tests: forall x. f[x] = f[x]; forall x y. f (x ++ y) == f y ++ f x. Now, what function is f?
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@anrizal f :: [a] -> [a]; f [] = []; Tests: forall x. f[x] = f[x]; forall x y. f (x ++ y) == f y ++ f x. Now, what function is f?