let * be a binary op. If (f*g)*h == f*(g*h) then * is associative. If f*U=f then U is identity of *. * is a monoid. If f, g, and h are functions and (f*g)(x) == f(g(x)) i.e. composition, then by associativity f*(g*h) == (f*g)*h == f(g(h(x))). i.e.: A pipeline.
Replying to @unclebobmartin
Still not right. Closer though.
7:16 AM - 13 Apr 2018
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