@debasishg In haskell, foldr f z x is the same as replacing all (:) with `f` and [] with z, so 1:2:3:[] becomes 1 `f` (2 `f` (3 `f` z))
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@debasishg In haskell, foldr f z x is the same as replacing all (:) with `f` and [] with z, so 1:2:3:[] becomes 1 `f` (2 `f` (3 `f` z))
