@dibblego @mwotton @damncabbage The term means one thing in maths and another in C++ already. Maybe they were using the C++ definition?
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Replying to @gregmcintyre
@gregmcintyre@mwotton@damncabbage Functor is (x->y)->(Fx->Fy) satisfying id and comp. No such thing here, even approximately (like C++).1 reply 0 retweets 0 likes -
Replying to @dibblego
@dibblego@mwotton@damncabbage In terms of the OT, I didn't mind Rob's amended code (2nd tweet). Not as nice as Haskell but easy to grok.1 reply 0 retweets 0 likes -
Replying to @gregmcintyre
@gregmcintyre@mwotton@damncabbage I think I missed that one. Twitter is awesome like that.1 reply 0 retweets 0 likes -
Replying to @dibblego
Gregory McIntyre Retweeted Rob Howard ଘ(੭ˊᵕˋ)੭
Gregory McIntyre added,
1 reply 0 retweets 0 likes -
Replying to @gregmcintyre
@gregmcintyre@mwotton@damncabbage This code is unrelated to the concept of a functor. I am getting confused.3 replies 0 retweets 0 likes -
Replying to @dibblego
@dibblego@gregmcintyre@damncabbage this was the original problem - the functors package was suggested, i bitched about the name.3 replies 0 retweets 0 likes -
Replying to @mwotton
@mwotton@dibblego@gregmcintyre@damncabbage In some mythologies functor = constant function https://github.com/mbostock/d3/wiki/Internals#functor …1 reply 0 retweets 0 likes -
Replying to @dysmemic
@pelotom@mwotton@gregmcintyre@damncabbage Fuck mate I'm just chillin here. Why you have to do that?1 reply 0 retweets 1 like -
Replying to @dibblego
@dibblego@mwotton@gregmcintyre@damncabbage remember, it's just names, and names are meaningless ;)3 replies 0 retweets 0 likes
@pelotom @mwotton @gregmcintyre @damncabbage AbstractWigglyTwoppedHoopyWrapperZipdiddyQuip has a meaning. Just ask me.
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