@gregmcintyre @mwotton @damncabbage FYI the link to the Ruby code misappropriates the word functor in an anti-knowledge manner.
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Replying to @dibblego
@dibblego@mwotton@damncabbage I don't even know what that code was hoping to achieve. Tears, presumably.1 reply 0 retweets 0 likes -
Replying to @gregmcintyre
@gregmcintyre@mwotton@damncabbage Yeah don't know. Just saying that the misuse of terms here is not benign.1 reply 0 retweets 0 likes -
Replying to @dibblego
@dibblego@mwotton@damncabbage The term means one thing in maths and another in C++ already. Maybe they were using the C++ definition?2 replies 0 retweets 0 likes -
Replying to @gregmcintyre
@gregmcintyre@mwotton@damncabbage Functor is (x->y)->(Fx->Fy) satisfying id and comp. No such thing here, even approximately (like C++).1 reply 0 retweets 0 likes -
Replying to @dibblego
@dibblego@mwotton@damncabbage In terms of the OT, I didn't mind Rob's amended code (2nd tweet). Not as nice as Haskell but easy to grok.1 reply 0 retweets 0 likes -
Replying to @gregmcintyre
@gregmcintyre@mwotton@damncabbage I think I missed that one. Twitter is awesome like that.1 reply 0 retweets 0 likes -
Replying to @dibblego
Gregory McIntyre Retweeted Rob Howard ଘ(੭ˊᵕˋ)੭
Gregory McIntyre added,
1 reply 0 retweets 0 likes -
Replying to @gregmcintyre
@gregmcintyre@mwotton@damncabbage This code is unrelated to the concept of a functor. I am getting confused.3 replies 0 retweets 0 likes -
Replying to @dibblego
@dibblego@gregmcintyre@damncabbage this was the original problem - the functors package was suggested, i bitched about the name.3 replies 0 retweets 0 likes
@mwotton @gregmcintyre @damncabbage Ruby cannot achieve non-trivial abstraction. It is intractable. Great exercise to try, for real.
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