@gregmcintyre @mwotton @damncabbage FYI the link to the Ruby code misappropriates the word functor in an anti-knowledge manner.
-
-
Replying to @dibblego
@dibblego@mwotton@damncabbage I don't even know what that code was hoping to achieve. Tears, presumably.1 reply 0 retweets 0 likes -
Replying to @gregmcintyre
@gregmcintyre@mwotton@damncabbage Yeah don't know. Just saying that the misuse of terms here is not benign.1 reply 0 retweets 0 likes -
Replying to @dibblego
@dibblego@mwotton@damncabbage The term means one thing in maths and another in C++ already. Maybe they were using the C++ definition?2 replies 0 retweets 0 likes -
Replying to @gregmcintyre
@gregmcintyre@mwotton@damncabbage Functor is (x->y)->(Fx->Fy) satisfying id and comp. No such thing here, even approximately (like C++).1 reply 0 retweets 0 likes -
Replying to @dibblego
@dibblego@mwotton@damncabbage In terms of the OT, I didn't mind Rob's amended code (2nd tweet). Not as nice as Haskell but easy to grok.1 reply 0 retweets 0 likes -
Replying to @gregmcintyre
@gregmcintyre@mwotton@damncabbage I think I missed that one. Twitter is awesome like that.1 reply 0 retweets 0 likes -
Replying to @dibblego
Gregory McIntyre Retweeted Rob Howard ଘ(੭ˊᵕˋ)੭
Gregory McIntyre added,
1 reply 0 retweets 0 likes -
Replying to @gregmcintyre
@gregmcintyre@mwotton@damncabbage This code is unrelated to the concept of a functor. I am getting confused.3 replies 0 retweets 0 likes -
Replying to @dibblego
@dibblego@mwotton@damncabbage Yes, not sure why Andy started talking functors. Maybe he saw a way to use them to do it nicely?1 reply 0 retweets 0 likes
@gregmcintyre @mwotton @damncabbage We did it in Ruby around 2008. It's highly recommended as an exercise, then throw the code away.
Loading seems to be taking a while.
Twitter may be over capacity or experiencing a momentary hiccup. Try again or visit Twitter Status for more information.