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dibblego's profile
Tony Morris
Tony Morris
Tony Morris
@dibblego

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Tony Morris

@dibblego

Power ∧ Attitude ⇒ Performance

Brisbane, Australia
tmorris.net
Joined May 2009

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    1. Tony Morris‏ @dibblego 8 Jun 2014
      Replying to @JulianBirch

      @JulianBirch @puffnfresh Got (f a -> b) use (<<=).

      2 replies 1 retweet 1 like
    2. The Unoriginal Angel‏ @JulianBirch 9 Jun 2014
      Replying to @dibblego

      @dibblego @bitemyapp @puffnfresh Can't find that one on hoogle... :(

      1 reply 0 retweets 0 likes
    3. Tony Morris‏ @dibblego 9 Jun 2014
      Replying to @JulianBirch

      @JulianBirch @bitemyapp @puffnfresh http://hackage.haskell.org/package/comonad-4.2/docs/src/Control-Comonad.html#%3C%3C%3D …

      1 reply 0 retweets 0 likes
    4. The Unoriginal Angel‏ @JulianBirch 9 Jun 2014
      Replying to @dibblego

      @dibblego @bitemyapp @puffnfresh Thanks. I think IObservable in C# forms a comonad, but I'm pretty sketchy on them.

      1 reply 0 retweets 0 likes
    5. Tony Morris‏ @dibblego 9 Jun 2014
      Replying to @JulianBirch

      @JulianBirch @bitemyapp @puffnfresh It's a semi-comonad. Don't let anyone tell you otherwise, because they will :)

      1 reply 0 retweets 0 likes
    6. The Unoriginal Angel‏ @JulianBirch 9 Jun 2014
      Replying to @dibblego

      @dibblego @bitemyapp @puffnfresh More to google :). Tbqh, I'm pretty sketchy on monad too, but I have lots of examples.

      1 reply 0 retweets 0 likes
    7. Tony Morris‏ @dibblego 9 Jun 2014
      Replying to @JulianBirch

      @JulianBirch @bitemyapp @puffnfresh IObservable has no extract; (a -> f a) for f=IObservable.

      1 reply 0 retweets 0 likes
    8. The Unoriginal Angel‏ @JulianBirch 9 Jun 2014
      Replying to @dibblego

      @dibblego @bitemyapp @puffnfresh (f a -> a)? e.g. get most recently transmitted value?

      1 reply 0 retweets 0 likes
    9. Tony Morris‏ @dibblego 9 Jun 2014
      Replying to @JulianBirch

      @JulianBirch @bitemyapp @puffnfresh How is it implemented?

      1 reply 0 retweets 0 likes
    10. The Unoriginal Angel‏ @JulianBirch 9 Jun 2014
      Replying to @dibblego

      @dibblego @bitemyapp @puffnfresh Sorry, was unclear, it's not. Just trying to make sure I understand.

      1 reply 0 retweets 0 likes
      Tony Morris‏ @dibblego 9 Jun 2014
      Replying to @JulianBirch

      @JulianBirch @bitemyapp @puffnfresh Provide an identity to extend that has the type Func<IObservable<A>, A>

      12:35 AM - 9 Jun 2014
      1 reply 0 retweets 0 likes
        1. The Unoriginal Angel‏ @JulianBirch 9 Jun 2014
          Replying to @dibblego

          @dibblego @bitemyapp @puffnfresh Gotcha. It needs the dual of pure/return to be a proper co-monad.

          0 replies 0 retweets 0 likes
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