Want an "f a -> f b"?
Got a->b? Use <$>
Got f (a->b)? Use <*>
Got a -> f b? Use =<<
#haskell
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@dibblego@bitemyapp@puffnfresh Thanks. I think IObservable in C# forms a comonad, but I'm pretty sketchy on them.
@JulianBirch @bitemyapp @puffnfresh It's a semi-comonad. Don't let anyone tell you otherwise, because they will :)
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@dibblego@bitemyapp@puffnfresh More to google :). Tbqh, I'm pretty sketchy on monad too, but I have lots of examples. -
@JulianBirch@bitemyapp@puffnfresh IObservable has no extract; (a -> f a) for f=IObservable. - Show replies
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