Want an "f a -> f b"?
Got a->b? Use <$>
Got f (a->b)? Use <*>
Got a -> f b? Use =<<
#haskell
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@dibblego@JulianBirch (b -> a) use (>$<) -
@puffnfresh@JulianBirch Should get profunctors to fit.
End of conversation
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@dibblego@bitemyapp@puffnfresh Can't find that one on hoogle... :( - Show replies
New conversation -
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