If the State Monad counts as pure I have a mutable ML memory location with monadic semantics to sell you
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Replying to @takeoutweight
@takeoutweight If it isn't pure, then nothing that allows function calls can be. *shrug*1 reply 0 retweets 0 likes -
Replying to @takeoutweight
@takeoutweight http://hackage.haskell.org/package/mtl-1.1.0.2/docs/src/Control-Monad-State-Lazy.html#State … operates only on persistent data structures, though. so it can't be the defn you're looking for.1 reply 0 retweets 0 likes -
Replying to @takeoutweight
@takeoutweight@mwotton That many people misuse a term, as you are doing, is not reasonable permission to reject its useful context.1 reply 0 retweets 0 likes -
Replying to @takeoutweight
@takeoutweight@mwotton An expression is pure if equational reasoning is preserved. Now show me where the State monad fails this.1 reply 0 retweets 0 likes
@takeoutweight @mwotton Back to the point, that you are misusing a term in awful ways doesn't mean it is meaningless.
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