@djspiewak @nuttycom @jdegoes @milessabin No, that is not a solid argument.
@djspiewak @nuttycom @jdegoes @milessabin No, you really haven't. And worse, not even close.
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@dibblego@nuttycom@jdegoes@milessabin Yes, I really have. Do you want me to instead show a type that has more than one valid Monad? -
@djspiewak@nuttycom@jdegoes@milessabin Yes, because I can't think of one and that will totally demonstrate your point! - Show replies
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