data BiFree f a b = Done a b | More (f (BiFree f a b)) -- is this a thing? #haskell
@jonsterling Yes, it's the binary functor property I am interested in potentially exploiting.
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data BiFree f a b = Done a b | More (f (BiFree f a b)) -- is this a thing? #haskell
@jonsterling Yes, it's the binary functor property I am interested in potentially exploiting.