Tony Morris

@djspiewak @casio_juarez no, my functions are pure. Yes, Haskell still performs effects.

@puffnfresh @casio_juarez Without impurity, you have no input, no output, and no evaluation.

@djspiewak @casio_juarez no, that's just wrong. IO is pure. There's no pretending.

@puffnfresh @casio_juarez Side effects are impure by definition. Your function has a result outside of it's return value.

@djspiewak @casio_juarez yes, IO is not side-effecting. It's effecting.

@puffnfresh @casio_juarez I have to know that IO represents an effectful container. If I didn’t know that, then I would see a and b as equal

@pigworker @puffnfresh @casio_juarez What if I said getLine = Just “foo”? IO is carrying a significance beyond mere valuation.