@dibblego Can't you just do another var f = x => x.Something(); ?
-
-
-
@TheColonial I want to do: a => { var x = Run(a); Something(x, x, a, ... - Show replies
New conversation -
-
-
@dibblego yes. You need to add a return in the multiline lambda though. -
@kfredt Sorry, can you show me the syntax? - Show replies
New conversation -
-
-
@dibblego Unless something has changed recently, you have to make a top-level method. -
@runarorama I got it working https://gist.github.com/3261215
End of conversation
New conversation -
Loading seems to be taking a while.
Twitter may be over capacity or experiencing a momentary hiccup. Try again or visit Twitter Status for more information.