@pervognsen I've always thought it was weird to call matrix multiplication's "n" the _dimension_ of the matrix...
@pervognsen That is always how I think of it, so I don't think of it as O(n^3), I think of it as O(n root n), so to speak :)
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@cmuratori@pervognsen I feel like I'm in the right on this one, though :P -
@cmuratori Because it's _not_ n^3 in the input, so you wouldn't expect it to "scale as the cube" of, you know, the data transfer time! - Show replies
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