@pervognsen Does this same approach work with two nonterminals by just adding a second operator, I assume?
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Replying to @cmuratori1 reply 1 retweet 3 likes
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Replying to @pervognsen
@pervognsen Oh snap... OK that is all super awesome. I am a fan of this.1 reply 0 retweets 1 like -
Replying to @cmuratori
@cmuratori Hopefully it's clear that this is mostly pure theory. Even if it's a very beautiful theory. :)1 reply 0 retweets 0 likes -
Replying to @pervognsen
@pervognsen That is what I actually wanted, because I was more trying to prove things than use it to code something, if that makes sense.1 reply 0 retweets 0 likes -
Replying to @cmuratori
@cmuratori@pervognsen Eg., when working on CFG code, sometimes you can write something but you do not really know if it is correct.1 reply 0 retweets 0 likes -
Replying to @cmuratori
@cmuratori@pervognsen Or if it is incorrect, is it incorrect in a way that affects the grammar you are using, etc.1 reply 0 retweets 0 likes -
Replying to @cmuratori
@cmuratori@pervognsen So being able to look at it in other ways is very helpful in that situation I think!1 reply 0 retweets 0 likes -
Replying to @cmuratori
@cmuratori If you haven't, I'd also suggest making sure you understand (and maybe implement) the CYK algorithm.1 reply 0 retweets 0 likes -
Replying to @pervognsen
@cmuratori It's the duh algorithm that uses that S matches a pattern XY and only if A matches X and B matches Y for some splitting S = AB.2 replies 0 retweets 0 likes
@pervognsen Roger that, I will take a look!
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