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cmuratori's profile
Casey Muratori
Casey Muratori
Casey Muratori
@cmuratori

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Casey Muratori

@cmuratori

I'm worried that the baby thinks people can't change.

Seattle
caseymuratori.com
Joined March 2009

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    1. Fabian Giesen‏ @rygorous 14 May 2015

      @cmuratori (HMH 119) Dude, the compiler *already* noticed that all the calcs involving PixelY and PixelY*axisBlah were loop invariant.

      1 reply 0 retweets 3 likes
    2. Fabian Giesen‏ @rygorous 14 May 2015
      Replying to @rygorous

      @cmuratori That's what I told you last Friday when you were puzzled why getting rid of the vector class was faster.

      1 reply 0 retweets 0 likes
    3. Fabian Giesen‏ @rygorous 14 May 2015
      Replying to @rygorous

      @cmuratori That was why. Spliting these calcs into scalars was what allowed the code motion to happen and made it much faster.

      1 reply 0 retweets 0 likes
    4. Fabian Giesen‏ @rygorous 14 May 2015
      Replying to @rygorous

      @cmuratori It had nothing to do with inlining. As I already said then. :)

      1 reply 0 retweets 0 likes
    5. Fabian Giesen‏ @rygorous 14 May 2015
      Replying to @rygorous

      @cmuratori That's also why your measured throughput is higher than the value you get from the clock count - several of these ops do not...

      1 reply 0 retweets 0 likes
    6. Fabian Giesen‏ @rygorous 14 May 2015
      Replying to @rygorous

      @cmuratori actually happen per pixel in the measured loop, since they are hoisted.

      1 reply 0 retweets 0 likes
    7. Fabian Giesen‏ @rygorous 14 May 2015
      Replying to @rygorous

      @cmuratori Eh, why your estimated total is higher than the observed clock count.

      1 reply 0 retweets 0 likes
    8. Fabian Giesen‏ @rygorous 14 May 2015
      Replying to @rygorous

      @cmuratori Nothing to do with issuing in parallel. The throughput already takes that into account.

      2 replies 0 retweets 0 likes
    9. Casey Muratori‏ @cmuratori 14 May 2015
      Replying to @rygorous

      @rygorous Wait, what do you mean by that - throughput takes into account parallel issuing _by unit_, but not between units, right?

      2 replies 0 retweets 1 like
      Casey Muratori‏ @cmuratori 14 May 2015

      @rygorous So if you have 10 adds and 10 muls, you could do them simultaneously, right, because they issue to different units.

      7:14 AM - 14 May 2015
      • 1 Like
      • (BLM) Sean Barrett
      1 reply 0 retweets 1 like
        1. New conversation
        2. Casey Muratori‏ @cmuratori 14 May 2015
          Replying to @cmuratori

          @rygorous So the throughput doesn't "take that into account", in that sense... you're just saying that _for the mul_ itself?

          1 reply 0 retweets 0 likes
        3. Casey Muratori‏ @cmuratori 14 May 2015
          Replying to @cmuratori

          @rygorous Anyway I will go look for hoistables so we can write it that way - I didn't realize we were still missing some :/

          1 reply 0 retweets 0 likes
        4. Show replies

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