@paniq @rygorous @Jonathan_Blow In other news, for your specific problem, you know the total rotation you need right?
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Replying to @cmuratori
@paniq@rygorous@Jonathan_Blow Because it's just the original rotation's conjugate times the new orientation.1 reply 0 retweets 0 likes -
Replying to @cmuratori
@paniq@rygorous@Jonathan_Blow So that gives you a quaternion that is the rotation you need to do over time.1 reply 0 retweets 0 likes -
Replying to @cmuratori
@paniq@rygorous@Jonathan_Blow And it's w component is cos(theta/2), so you know the angle is 2*acos(w) if you want it. Etc., etc.1 reply 0 retweets 0 likes
@paniq @rygorous @Jonathan_Blow I don't know why I'm spamming all these quaternion things. I will stop now.
7:02 PM - 11 Mar 2015
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