@paniq @rygorous @Jonathan_Blow In other news, for your specific problem, you know the total rotation you need right?
@paniq @rygorous @Jonathan_Blow Because it's just the original rotation's conjugate times the new orientation.
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@paniq@rygorous@Jonathan_Blow So that gives you a quaternion that is the rotation you need to do over time. -
@paniq@rygorous@Jonathan_Blow And it's w component is cos(theta/2), so you know the angle is 2*acos(w) if you want it. Etc., etc. - Show replies
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