So, there are 707 per 100,000 in the system. Which means that there are 999,293 per 100,000 who aren't. How does this support Boudin's claim that a "majority" of us have family members in prison?
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US currently incarcerates 2.3MM (way too many, I agree), but there are ~129MM households in the US. For the majority of households to have at least 1 member incarcerated, we would need 65MM prisoners minimum. For
@chesaboudin to not be a liar, we better start imprisoning & fast.pic.twitter.com/5sAngFJXBD
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To be fair, no-one told Chesa that there would be math in the job.
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Replying to @dwbudd @EsmeAlaki and
Just so we’re clear, the “math” offered above, estimating that 65MM Americans would need to be incarcerated for Chesa’s stmt to be true, is wrong in every possible respect. Just dead wrong.
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Replying to @borrfdad @EsmeAlaki and
The estimate of 65 mm requires almost maximum entropy (ie, that one and only one member per household s in prison). It presumes a lot of other things as well. But Chesa’s claim is embarrassingly wrong.
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Words like “majority?” (Even in the tendentious “study” you cite, 45% is not a majority by any definition that I’m aware of).
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Replying to @dwbudd @EsmeAlaki and
I don’t know where Chesa is getting his number. This is just one estimate. But I can tell ya that 45 is a hell of a lot closer to 50 than 2.5M is to 65m, and yet a second ago you were cheering that half assed back of the envelope math
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Replying to @borrfdad @EsmeAlaki and
Trump got 46% of the vote in 2016. Is that the “majority?” Chesa was wrong two ways to Sunday. And while we are at it, the guys his parents helped kill were working class men trying to earn a living.
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