The City of Milwaukee says 18,803 people voted in person today. Another 56,489 have returned absentee ballots, with as many as 40,223 still potentially in transit (issued but not yet returned). Total turnout: at least 75,292.
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In the 2016 spring election, 167,765 people voted in the City of Milwaukee, so this is a steep, steep dropoff.
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Oh, ok. Thanks,
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Exactly how republicans wanted it to go
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That was a very competitive primary driving higher turnout though right? Last year when it was primarily just for Supreme Court it was 68,770. 2018 was 58,384 and 2017 was 45,780.
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The
@GOP got its wish grantedThanks. Twitter will use this to make your timeline better. UndoUndo
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It's a 10% increase over last year though
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Perfectly scripted to the
@GOP voter suppression plan.Thanks. Twitter will use this to make your timeline better. UndoUndo
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Does not include the absentees.
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In last year’s Supreme Court race, there were 68,770 ballots cast in the city of Milwaukee. This is an improvement from that standpoint if focused on that race and not the presidential primary aspect (which possibly many Wisconsinites were).
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I think you'd have to expect turnout would be higher with a presidential primary on the ballot than for *just* a judicial race. But lower than 2016 seems likely.
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