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avibryant's profile
Avi Bryant
Avi Bryant
Avi Bryant
@avibryant

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Avi Bryant

@avibryant

Happiest when working on Random Forests from random beaches.

Galiano Island
avibryant.com
Joined November 2006

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    1. le Chep‏ @c_chep 13 Feb 2016
      Replying to @scalding

      le Chep Retweeted le Chep

      .@scalding on second thought (a night's rest helped^^), this can't possibly work except in the https://twitter.com/c_chep/status/698156209094967298 … very limited case…

      le Chep added,

      le Chep @c_chep
      Replying to @c_chep
      Ugly but convenient and not that painful after all https://gist.github.com/cchepelov/746826f18af8db7e9d04 … pic.twitter.com/daIrlDdkvu
      1 reply 0 retweets 0 likes
    2. le Chep‏ @c_chep 13 Feb 2016
      Replying to @c_chep

      … as if you're changing the keys' domain, you ARE going to require a shuffle, which .toTypedPipe.map(…).group provides @scalding

      2 replies 0 retweets 0 likes
    3. Scalding‏ @scalding 13 Feb 2016
      Replying to @c_chep

      @c_chep you have a bijection=>won't break the grouping. So all contracts are preserved. Don't need reshuffle just transform before mapGroup

      1 reply 0 retweets 0 likes
    4. le Chep‏ @c_chep 13 Feb 2016
      Replying to @scalding

      @scalding true, indeed! Will file the issue

      1 reply 0 retweets 0 likes
    5. Avi Bryant‏ @avibryant 13 Feb 2016
      Replying to @c_chep

      @c_chep @scalding injection should be enough for the contract.

      2 replies 0 retweets 0 likes
    6. Ian O'Connell‏ @0x138 13 Feb 2016
      Replying to @avibryant

      @avibryant @c_chep @scalding bijection only works if the ordering/equality all hold I think.

      1 reply 0 retweets 0 likes
    7. Ian O'Connell‏ @0x138 13 Feb 2016
      Replying to @0x138

      @avibryant @c_chep @scalding Comparators might not use all fields so matches might not align

      1 reply 0 retweets 0 likes
    8. Avi Bryant‏ @avibryant 13 Feb 2016
      Replying to @0x138

      @0x138 @c_chep @scalding I'm thinking of this as a reduce-side transformation, in which case it wouldn't matter, right?

      1 reply 0 retweets 0 likes
    9. Ian O'Connell‏ @0x138 13 Feb 2016
      Replying to @avibryant

      @avibryant @c_chep @scalding If you keep as a CoGrouped[K1, V] you 'should' be able to join that with another CoGrouped[K1, V2]

      1 reply 0 retweets 0 likes
    10. Ian O'Connell‏ @0x138 13 Feb 2016
      Replying to @0x138

      @avibryant @c_chep @scalding If you do that reduce side the shuffles will occur on different types/orderings which would be bad I think.

      1 reply 0 retweets 1 like
      Avi Bryant‏ @avibryant 13 Feb 2016
      Replying to @0x138

      @0x138 @c_chep @scalding in which case maybe you do need the bijection (transform one or the other map side so they match, then maybe back)

      12:27 PM - 13 Feb 2016
      • 1 Like
      • P. Oscar Boykin
      2 replies 0 retweets 1 like
        1. le Chep‏ @c_chep 13 Feb 2016
          Replying to @avibryant

          @avibryant exactly my concern (in the generalised case; in my practice where K1 is K@@T, ordering is kt.unwrap's ord) @0x138 @scalding

          0 replies 0 retweets 0 likes
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        1. Ian O'Connell‏ @0x138 13 Feb 2016
          Replying to @avibryant

          @avibryant @c_chep @scalding If you do that then you would ignore the ordering/comparator of the original type in the shuffle I believe.

          0 replies 0 retweets 0 likes
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