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avibryant's profile
Avi Bryant
Avi Bryant
Avi Bryant
@avibryant

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Avi Bryant

@avibryant

Happiest when working on Random Forests from random beaches.

Galiano Island
avibryant.com
Joined November 2006

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    1. Jeff Sarnat‏ @Eigenvariable 28 Dec 2015

      One of the few places where I wish Scala's type system were _more_ powerful: existential types.

      1 reply 0 retweets 4 likes
    2. empanada linguist‏ @jco 28 Dec 2015
      Replying to @Eigenvariable

      @Eigenvariable what aspect? ML style stuff, type inference, ??

      1 reply 0 retweets 0 likes
    3. Jeff Sarnat‏ @Eigenvariable 28 Dec 2015
      Replying to @jco

      @jco AFAICT, it has no elimination/unpack operator, i.e. given x: Foo[A] forSome { type A } you can't define anything else in terms of x.A.

      2 replies 0 retweets 0 likes
    4. empanada linguist‏ @jco 28 Dec 2015
      Replying to @Eigenvariable

      @Eigenvariable ah, I see. Yeah... If you don't control Foo you can make Foo2 which has a type member and use that

      1 reply 0 retweets 0 likes
    5. Jeff Sarnat‏ @Eigenvariable 28 Dec 2015
      Replying to @jco

      @jco That's where I started, and now that I'm programming with such a thing I find myself wanting real existential types (strong or weak).

      1 reply 0 retweets 0 likes
    6. empanada linguist‏ @jco 28 Dec 2015
      Replying to @Eigenvariable

      @Eigenvariable ah I see. Makes sense. Yeah the relationship between type parameters and type members is so ugly

      1 reply 0 retweets 0 likes
      Avi Bryant‏ @avibryant 28 Dec 2015
      Replying to @jco

      @jco @Eigenvariable yeah - I feel like scala probably provides the tools to do what you need in most of these cases but not elegantly.

      10:51 AM - 28 Dec 2015
      1 reply 0 retweets 0 likes
        1. New conversation
        2. Avi Bryant‏ @avibryant 28 Dec 2015
          Replying to @avibryant

          @jco @Eigenvariable and for me anyway it's right on the edge of "I have no idea what I'm doing but can poke at it til it works" territory

          2 replies 0 retweets 1 like
        3. Jeff Sarnat‏ @Eigenvariable 28 Dec 2015
          Replying to @avibryant

          @avibryant @jco I understand the theory of existential types pretty well, and AFAICT Scala is simply missing a very important primitive.

          2 replies 0 retweets 0 likes
        4. Avi Bryant‏ @avibryant 28 Dec 2015
          Replying to @Eigenvariable

          @Eigenvariable well, like @jco says, it provides it via type members. That's just hella awkward sometimes.

          1 reply 0 retweets 0 likes
        5. Avi Bryant‏ @avibryant 28 Dec 2015
          Replying to @avibryant

          @Eigenvariable @jco (but also I *don't* have a good grasp of theory so am probably missing something :)

          1 reply 0 retweets 0 likes
        6. empanada linguist‏ @jco 28 Dec 2015
          Replying to @avibryant

          @avibryant @Eigenvariable Jeff, dunno if you can be bothered, but a gist of what you wished you could do and what you actually did would be+

          1 reply 0 retweets 0 likes
        7. empanada linguist‏ @jco 28 Dec 2015
          Replying to @jco

          @avibryant @Eigenvariable interesting

          1 reply 0 retweets 0 likes
        8. Jeff Sarnat‏ @Eigenvariable 28 Dec 2015
          Replying to @jco

          @jco @avibryant I'll see what I can come up with. Basically I have a list whose elements all have abstract types...

          1 reply 0 retweets 0 likes
        9. Jeff Sarnat‏ @Eigenvariable 28 Dec 2015
          Replying to @Eigenvariable

          @jco @avibryant and I want to iterate over that to return a function whose type is calculated in terms of the elements of the list.

          2 replies 0 retweets 0 likes
        10. 7 more replies

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