'(·)@allgebrah·Nov 10, 2016did you know there's a sufficient, probably complete simulacrum of you inside a newcomb predictor? HANG ON WE'LL GET YOU OUT OF THERE4323
mcc@mcclure111·Nov 10, 2016Replying to @allgebrahI'm looking at the description of the Newcomb paradox & don't understand why "take box A and storm out" isn't a considered option11
'(·)@allgebrah·Nov 10, 2016Replying to @mcclure111purely formally, you could choose A+B for an at least equally good outcome2
'(·)@allgebrah·Nov 10, 2016Replying to @allgebrah and @mcclure111I was thinking though, maybe you could coax computation worth more than $1M out of the predictor21
'(·)@allgebrah·Nov 10, 2016Replying to @allgebrah and @mcclure111this is hard though since the effort is symmetrical; maybe if works if the predictor classically simulates quantum decisions?1
mcc@mcclure111·Nov 10, 2016Replying to @allgebrahthe problem I see with your proposal really is it may assume we get multiple gos to extract multiple bits2
'(·)@allgebrahReplying to @mcclure111one bit only https://twitter.com/allgebrah/status/796846552925016064… you could probably pull major shenanigans with more than oneQuote Tweet'(·)@allgebrah·Nov 10, 2016Replying to @allgebrahYou have one bit to communicate to the outside. Do you one-AI-box or two-AI-box?11:16 PM · Nov 10, 2016·Twitter Web Client
mcc@mcclure111·Nov 10, 2016Replying to @allgebrahhere is an analysis i wrote once on a related subject http://ask.fm/mcclure111/answers/117203677762…1
'(·)@allgebrah·Nov 10, 2016Replying to @mcclure111B is also really useful in case the sidewalk is a light-year long but you need to know now11