The idea that there is such a thing as analogue computation is a classic oxymoron. The logic of the digital is computation and vice versa. (Now let's see how quickly this thread devolves.)
-
-
Replying to @NegarestaniReza
the analog computers I've played with (homebrew systems from http://www.analogmuseum.org/english/examples/ …) were not digital at all, it was more like plugging modular synthesizers and making curves on an oscilloscope converge
2 replies 1 retweet 5 likes -
Replying to @allgebrah
How many times should I say this, they are computers, the word computer is being used loosely here.
1 reply 0 retweets 0 likes -
Replying to @NegarestaniReza
Seems like word games to me. The theory of these things is not rooted in discrete math, they only become digital when you assume a digital universe.
1 reply 0 retweets 3 likes -
Replying to @allgebrah
You sound like one of those artists who when someone says computation, they instantly think of Silicon Valley or some unholy pan-computationalist thesis.
3 replies 0 retweets 3 likes -
Replying to @NegarestaniReza
eh? How else do you want to root analog computers in discrete math then? You could make an argument about branches being discrete for example, though my experience has been that I didn't use any branches at all really. You'd totally get emerging bifurcations though
1 reply 0 retweets 0 likes -
Replying to @allgebrah
I just think you think discreet math is like a pure black and white movie. It is not. Once you have a thesis about effective computation you can equip it with fuzzy logics of all sorts. That's not a problem.
1 reply 0 retweets 1 like -
Replying to @NegarestaniReza
I was using "discrete" as a stand-in for "digital" because I can count only integers (with certain tricks, rationals) on my fingers (digits). Maybe yours can count reals, in which case yeah cool, go ahead call your fuzzy logics digital!
1 reply 0 retweets 1 like
More interesting would be a way to map an analog computer's bifurcations to such a logic and then showing equivalence, that's an equivalence I'd buy because it'd only have to assume measurement imprecisions. I'd read that.
Loading seems to be taking a while.
Twitter may be over capacity or experiencing a momentary hiccup. Try again or visit Twitter Status for more information.