@puellavulnerata I think there's a way to do it as a bijection, not 100% sure.
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Replying to @St_Rev
@puellavulnerata ah yeah 1/3 of the way down this http://math.stackexchange.com/questions/7643/produce-an-explicit-bijection-between-rationals-and-naturals … (it's pretty clever)1 reply 0 retweets 0 likes -
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Replying to @puellavulnerata
@puellavulnerata It's more complex, involves creating integer partitions like {2, 0, -1, 3} and turning them into 2^2 * 5^0 * 7^-1 * 11^31 reply 0 retweets 0 likes -
Replying to @St_Rev
@puellavulnerata That way you never worry about cancellation.1 reply 0 retweets 0 likes -
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Replying to @puellavulnerata
@puellavulnerata Yeah, I think the gimmick is something like factor 60 = 2^2 x 3^1 x 5^1 and then +- the exponents to get 15/4, 20/3, 12/5..1 reply 0 retweets 1 like -
Replying to @St_Rev
@puellavulnerata ...so if n has i factors you have 2^i ways to allocate the prime powers to numerator vs denominator.1 reply 0 retweets 0 likes
@puellavulnerata ...which is not how you ACTUALLY do it but it's the germ of the idea I think
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. Banned in Sweden. SubGenius, Zhuangist, white-hat troll. Defrocked mathematician. Brain problems.