@MoogleHariant @GabrielDuquette Yeah, that's better than mine. (Really not having a good brain day/week/year)
@MoogleHariant @GabrielDuquette My solution: Let each side be length 2. Each altitude divides the triangle into 2 30-60-90 triangles.
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@MoogleHariant
@GabrielDuquette By Pythagorean thm, sides 1:sqrt(3):2. One of the other altitudes splits that triangle into 2 smaller ones. -
@MoogleHariant
@GabrielDuquette One of those is also a 30:60:90 triangle. Because the side ratios have to be 1:sqrt(3):2... -
@MoogleHariant
@GabrielDuquette ...the distance from the base to the center has to be 1/sqrt(3). Which is 1/3 sqrt(3), not 1/2. -
@MoogleHariant
@GabrielDuquette So the center is 1/3 of the way up the altitude, not 1/2 the way.
End of conversation
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. Banned in Sweden. SubGenius, Zhuangist, white-hat troll. Defrocked mathematician. Brain problems.