@sarahdoingthing For disease A, suppose P(A | QQ) = P_1 and P(A | !QQ) = P_2. That's 2 completely independent numbers.
@sarahdoingthing But the narrow heritability h^2 is a single number that depends on both P_1 and P_2. So it's impossible to reconstruct them
12:37 PM - 17 Aug 2014
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. Banned in Sweden. SubGenius, Zhuangist, white-hat troll. Defrocked mathematician. Brain problems.