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St_Rev's profile
St. Rev ☯️🏴😻
St. Rev ☯️🏴😻
St. Rev  ☯️ 🏴 😻
@St_Rev

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St. Rev  ☯️ 🏴 😻

@St_Rev

Anti-authoritarian, bleeding-heart Stirnerite, ☯️. Banned in Sweden. SubGenius, Zhuangist, white-hat troll. Defrocked mathematician. Brain problems.

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Joined May 2011

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    1. TheWakalix‏ @TWakalix Jul 6
      • Report Tweet
      Replying to @St_Rev @AnnKSterzinger

      I think the key word is “number”. What’s a number? Is the ring Z_p numbers (where p is prime)?

      2 replies 0 retweets 0 likes
    2. TheWakalix‏ @TWakalix Jul 6
      • Report Tweet
      Replying to @TWakalix @St_Rev @AnnKSterzinger

      Which I recognize is pretty redundant with your subsequent tweets that went into the true statement that Quanta mangled, but eh

      2 replies 0 retweets 0 likes
    3. AnnKSterzinger‏ @AnnKSterzinger Jul 6
      • Report Tweet
      Replying to @TWakalix @St_Rev

      By the way, no one has ever explained "i" to me in a way that makes sense. I think my calculus teacher was just like "'i' stands for imaginary, OK?" and then grunted and went back to staring out the window.

      2 replies 0 retweets 0 likes
    4. TheWakalix‏ @TWakalix Jul 6
      • Report Tweet
      Replying to @AnnKSterzinger @St_Rev

      i shows up in enough contexts that there are multiple ways to go about explaining it. The standard, I think, is i = sqrt(-1), but there’s also a geometrical explanation (complex numbers as isomorphic to vectors) and a quaternion-style explanation (i^2 = -1, 1 * i = i).

      1 reply 0 retweets 1 like
    5. TheWakalix‏ @TWakalix Jul 6
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      Replying to @TWakalix @AnnKSterzinger @St_Rev

      First way: no real number squared is ever negative. This means that the square root of -1 doesn’t exist. But if we pretend it does, it has to be a new number, not an existing one. Following the standard rules of numbers, we can add and multiply between normal numbers and i.

      1 reply 0 retweets 1 like
    6. AnnKSterzinger‏ @AnnKSterzinger Jul 6
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      Replying to @TWakalix @St_Rev

      It's a bit bizarre to me that you can invent a number and it still works with the standard rules of numbers.

      1 reply 0 retweets 0 likes
    7. St. Rev  ☯️ 🏴 😻‏ @St_Rev Jul 6
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      Replying to @AnnKSterzinger @TWakalix

      Sometimes you can, sometimes you can't! Like, I could say "Let z be a real number such that z = 1 and z = 0" and this would be Extremely Bad because the universe would collapse.

      1 reply 0 retweets 2 likes
    8. St. Rev  ☯️ 🏴 😻‏ @St_Rev Jul 6
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      Replying to @St_Rev @AnnKSterzinger @TWakalix

      This was actually a plot point on Rick and Morty, come to think of it. Anyway, inventing a number and throwing it in the bag is what mathematicians call 'adjoining an element'. You just have to check that everything still works and figure out the consequences.

      2 replies 0 retweets 1 like
    9. St. Rev  ☯️ 🏴 😻‏ @St_Rev Jul 6
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      Replying to @St_Rev @AnnKSterzinger @TWakalix

      So with 'i' the process goes, informally, something like... ok we still have all the real numbers like 3 and pi. 'let a be a real number' Multiplication means we have stuff like 12i and -i/4. 'bi, where b is a real number' Addition means we have pairs like 3 + 12i and pi - i/4.

      1 reply 0 retweets 0 likes
    10. St. Rev  ☯️ 🏴 😻‏ @St_Rev Jul 6
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      Replying to @St_Rev @AnnKSterzinger @TWakalix

      So we at least have to handle everything that looks like 'a + bi, where a and b are real numbers' It turns out that this is all you need -- you can add, subtract, multiply and divide these guys and you don't get anything hairier than 'a + bi'.

      1 reply 0 retweets 0 likes
      St. Rev  ☯️ 🏴 😻‏ @St_Rev Jul 6
      • Report Tweet
      Replying to @St_Rev @AnnKSterzinger @TWakalix

      It takes some checking -- proving division works is a bit of a slog. But this is the kind of thing we algebraists do for a living.

      1:27 PM - 6 Jul 2019
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      • AnnKSterzinger
      0 replies 0 retweets 1 like

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