the last part of this bit of the C standard is uncoolpic.twitter.com/RTvpNc7dtd
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If they're numerically equal, they're equal? Um... yes? Not sure what you're saying here.
The quoted text just says the compiler doesn't have to insert gratuitous padding so that &foo[one_past_end]!=&bar.
It's @johnregehr quoting the C standard—does he still need to say he's discussing (possible) undefined behavior? Seehttps://twitter.com/Myriachan/status/890311339570118656 …
Sorry, I still don't see the problem? If (unsigned long)x==(unsigned long)y then x==y. Programmer's the one comparing out of bounds...
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