super quick post "Do Expressive Programming Languages Always Have Undefined Behavior?" https://blog.regehr.org/archives/1476 also see Betteridge's law
It's mainly RoT, %p, and perhaps some things about newly allocated memory lacking effective type.
-
-
%p isn't UB though, it's just implementation-defined. also what's RoT
-
%p is equivalent to RoT because you can printf-modify-scanf pointers.
-
And RoT is 6.2.6.
End of conversation
New conversation -
Loading seems to be taking a while.
Twitter may be over capacity or experiencing a momentary hiccup. Try again or visit Twitter Status for more information.