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RichFelker's profile
Rich Felker
Rich Felker
Rich Felker
@RichFelker

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Rich Felker

@RichFelker

Yeah, I do @musllibc, FOSS & infosec stuff. But now is not the time for a mostly-/only-tech Twitter feed.

musl-libc.org
Joined March 2014

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    1. Rich Felker‏ @RichFelker 14 May 2016
      Replying to @ch3root

      All opt takes place by "as if" rule. Optimizations that violate that are not valid. Changing observable behavior is a bug

      2 replies 0 retweets 0 likes
    2. Alexander Cherepanov‏ @ch3root 14 May 2016
      Replying to @RichFelker

      Sure. Everything boils down to the question what "observable behavior" is.

      1 reply 0 retweets 0 likes
    3. Alexander Cherepanov‏ @ch3root 14 May 2016
      Replying to @ch3root @RichFelker

      The amount of used memory is not part of observable behavior. In the same way as the execution time is not.

      3 replies 0 retweets 0 likes
    4. Alexander Cherepanov‏ @ch3root 14 May 2016
      Replying to @ch3root @RichFelker

      Take "int main() { char s[10000000] = {0}; }". It segfaults with -O0 but not with -O3. Is this invalid optimization?

      3 replies 0 retweets 0 likes
    5. Rich Felker‏ @RichFelker 14 May 2016
      Replying to @ch3root

      No because the original program has UB (by overflowing stack). C std actually omits this but it's obvious.

      2 replies 0 retweets 0 likes
    6. Alexander Cherepanov‏ @ch3root 15 May 2016
      Replying to @RichFelker

      I don't think you can label it as UB that easy. Whether something UB or not is decided based on the std alone and\

      2 replies 0 retweets 0 likes
    7. Rich Felker‏ @RichFelker 15 May 2016
      Replying to @ch3root

      I label SO as UB because the standard leaves it undefined by omission of any attempt to resolve contradictions around it.

      1 reply 0 retweets 0 likes
    8. Alexander Cherepanov‏ @ch3root 15 May 2016
      Replying to @RichFelker

      Well, the standard doesn't mention stack at all. One way to look at it is that, hence, there are no restrictions on\

      1 reply 0 retweets 0 likes
    9. Alexander Cherepanov‏ @ch3root 15 May 2016
      Replying to @ch3root @RichFelker

      a program related to stack. Thus, all implementation using stack are not conforming.

      1 reply 0 retweets 0 likes
    10. Alexander Cherepanov‏ @ch3root 15 May 2016
      Replying to @ch3root @RichFelker

      But as you mentioned memory is limited in practice, stack or not. And there are similar problems with static vars.

      2 replies 0 retweets 0 likes
      Rich Felker‏ @RichFelker 15 May 2016
      Replying to @ch3root

      You can ignore the word "stack". Problem is that the C std ignores inherent finitude of automatic storage.

      6:30 PM - 15 May 2016
      0 replies 0 retweets 0 likes

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