@spun_off Where a size expression is part of the operand of a sizeof operator and changing the value of the size expression would not affect
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@RichFelker “idiotic”only applied to the phrase using a notion that hadn't been defined & before I had had coffee.Thanks. Twitter will use this to make your timeline better. UndoUndo
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@RichFelker @spun_off@whitequark wait, how’s that? -
@comex perhaps Rich means something like: char t[X]; sizeof(R=1, t) // set R iff X is not a compile-time constant Or some more useful form. -
@spun_off
@RichFelker and even then, I don’t think you can tell… well, I’ll wait for his explanation - End of conversation
New conversation -
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