int a[20], b[20], *p = a, i; if ((uintptr_t)(a + 20) == (uintptr_t)b) { b[5] = 1; for (i = 0; i < 40; i++) *p++ = 0; printf("%d\n", b[5]); }
@ch3root I probably confused this issue too much already with mistyped (on Android kb) tweets; let's continue it elsewhere.
-
-
Thanks. Twitter will use this to make your timeline better. UndoUndo
-
Loading seems to be taking a while.
Twitter may be over capacity or experiencing a momentary hiccup. Try again or visit Twitter Status for more information.