#define D(c) x = (x & ((1<<c)-1)) + (x >> c);
unsigned mod5(unsigned x) {D(16) D(8) D(4) D(4) D(4) x = (x&3)-(x>>2); return (x>3) * 5 + x;}
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@RichFelker@ch3root Of course, we don't mean this for actual use in C on today's typical CPU archs. We merely express it in C. -
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@RichFelker@solardiz Yeah, I don't like it too. But it saves some chars in a tweet. Perhaps it's better to leave some spaces out instead. -
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