body { -ms-overflow-style: scrollbar; overflow-y: scroll; overscroll-behavior-y: none; } .errorContainer { background-color: #FFF; color: #0F1419; max-width: 600px; margin: 0 auto; padding: 10%; font-family: Helvetica, sans-serif; font-size: 16px; } .errorButton { margin: 3em 0; } .errorButton a { background: #1DA1F2; border-radius: 2.5em; color: white; padding: 1em 2em; text-decoration: none; } .errorButton a:hover, .errorButton a:focus { background: rgb(26, 145, 218); } .errorFooter { color: #657786; font-size: 80%; line-height: 1.5; padding: 1em 0; } .errorFooter a, .errorFooter a:visited { color: #657786; text-decoration: none; padding-right: 1em; } .errorFooter a:hover, .errorFooter a:active { text-decoration: underline; } #placeholder, #react-root { display: none !important; } body { background-color: #FFF !important; }

JavaScript is not available.

We’ve detected that JavaScript is disabled in this browser. Please enable JavaScript or switch to a supported browser to continue using twitter.com. You can see a list of supported browsers in our Help Center.

Terms of Service Privacy Policy Cookie Policy Imprint Ads info © 2023 Twitter, Inc.

Conversation

A demonstration for this Ramanujan nested radical [source, video by MindYourDecisions: buff.ly/2okbWjB] [more info about Srinivasa Ramanujan -> buff.ly/2ojQpHK]

Embedded video

GIF

7:02 AM · Jul 4, 2022

Replying to

1=sqrt(1+0*...) 2=sqrt(1+1*...) Could we generalize this to negative integers or Gaussian integers?

Replying to

Quote Tweet

This derivation may look convincing, but the exact same process can be used to "prove" that the expression equals 4, or any real number greater than 3. See this excellent video from @Mathologer for more details: youtu.be/leFep9yt3JY

1

Replying to

and

Quindi 3 è il numero perfetto

Replying to

Start with 2.

Replying to

😀😀 wow great greatly ...

@Nature_cogitat

Replying to

First three steps are enough remaining is just iteration.