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this gets you log 2 = log 3/2 + log 4/3 = 2 sum (1/3)^{2n-1} / (2n-1), whose terms grow like a power of 9 instead of like a power of 2 and so which converges more than 3 times as quickly (in the sense that you get more than 3 times as many digits of accuracy per term)
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