No #bitcoin is NOT O(n^2) in terms of bandwidth. Every node has a fixed set of connections. Bandwidth is O(n).
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@Datavetaren@Nightwolf42 Increasing C (i.e. treating as not a constant after all) is a good general strategy for reducing these risks. -
@NickSzabo4@Nightwolf42 1) Instread of imcreasing "constant" C, why not randomly switch to new adresses stochasticly on a regular basis? -
@NickSzabo4@Nightwolf42 2) Who says function of C is a linear function of N? Could be logN => O(N log N).
End of conversation
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