It may also be worthwhile to consult the original link https://www.cut-the-knot.org/Probability/RightStrategy.shtml …
It's worth reading through @nntaleb's tweets, then digesting @CutTheKnotMath's problem, and then finally solving the problem (or checking @ThamizhKudimagn's solution).https://twitter.com/nntaleb/status/978348830176546819 …
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As a general rule of thumb, under disadvantageous play you want to play bold as few times as possible. Note A must win at least 1 game, so A plays bold in game 1. If A wins, A plays a conservative game; if drawn, A plays bold. If A loses game 1, A plays bold again.
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