A problem from an old @CruxMathematicorum https://www.cut-the-knot.org/m/Geometry/DiagonalsInPolygon.shtml … #FigureThat #math #geometrypic.twitter.com/HkQ3Mhl2Jc
-
Just for once, trying to read across several tweets, "...we have n-1+1 parallel line segments, each with a pair of unique vertices (2n total)" is suspect: you try to include the second side which you know nothing about
I was on phone my phone. I had no choice at the time of writing. If it helps I'm happy make an image and tweet it. I don't understand what you're saying. Let n = 3, there's an average of 9/6 = 1.5 diagonals parallel to each side. Round it up to 2, for one side.
-
-
Just read what you wrote (the sentence I quoted). As I see it: 2n vertices is all you have; n parallel segments joining 2n vertices necessarily include 2 sides. Just try to consolidate your tweets when you have time
-
Does this make it clearer and would you now consider the problem solved by this solution? Thank you.pic.twitter.com/gNV3qO7QuR
- 8 more replies
New conversation -
-
-
So one side, has two unique diagonals that are parallel to each other and to the side. In a convex 6-gon, there is no way to build a shape with 2 parallel diagonals and a 3rd parallel side. I don't know what the "second side" you're referring to would be.
Thanks. Twitter will use this to make your timeline better. UndoUndo
-
Loading seems to be taking a while.
Twitter may be over capacity or experiencing a momentary hiccup. Try again or visit Twitter Status for more information.