Probability of a Meet in an Elimination Tournament https://www.cut-the-knot.org/Probability/EliminationTournament.shtml … #FigureThat #math #probabilitypic.twitter.com/wjEuVUAna2
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Probability of a Meet in an Elimination Tournament https://www.cut-the-knot.org/Probability/EliminationTournament.shtml … #FigureThat #math #probabilitypic.twitter.com/wjEuVUAna2
16*31 pairs, 31 games, 1/16 probability
Why does it make sense to divide the number of games played (31) with the number of pairings (32 Choose 2 = 16*31)?
All pairings are equiprobable since players have the same strength and a given pairing can only happen once
Thanks! I knew that but, didn't make the connection between your point and the below: Incorrect: 1/496 + 1/495 + 1/494 + 1/493 + ... + 1/435 Correct: 1/496 + 1/496 + 1/496 + ... + 1/496 = 31/(16*31)
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